Question

The value of $3{\csc }^2{60}^0-2{\cot }^2{30}^0+{\sec }^2{45}^0=$

Answer 1

To Prove: $3{\csc }^2{60}^0-2{\cot }^2{30}^0+{\sec }^2{45}^0=0$
L.H.S: $3{\csc }^2{60}^0-2{\cot }^2{30}^0+{\sec }^2{45}^0$
= $3(\frac{2}{\sqrt{3}}{)}^2-2(\sqrt{3}{)}^2+(\sqrt{2}{)}^2$
= $4-6+2$
= $0$
Thus, L.H.S. = R.H.S.