Question

The value of
$3\frac{1}{12}-\left[1\frac{3}{4}+\left\{2\frac{1}{2}-\left(1\frac{1}{2}-\frac{1}{3}\right)\right\}\right]$ is

• A. $\frac{1}{2}$
• B. $2$
• C. $1$
• D. $0$

Answer 1

The correct option is D $0$

$3\frac{1}{12}-\left[1\frac{3}{4}+\left\{2\frac{1}{2}-\left(1\frac{1}{2}-\frac{1}{3}\right)\right\}\right]$

$=\frac{37}{12}-\left[\frac{7}{4}+\left\{\frac{5}{2}-\left(\frac{3}{2}-\frac{1}{3}\right)\right\}\right]$

$=\frac{37}{12}-\left[\frac{7}{4}+\left(\frac{5}{2}-\frac{(9-2)}{6}\right)\right]$

$=\frac{37}{12}-\left[\frac{7}{4}+\left(\frac{5}{2}-\frac{7}{6}\right)\right]$

$=\frac{37}{12}-\left[\frac{7}{4}+\frac{(15-7)}{6}\right]$

$=\frac{37}{12}-\left[\frac{7}{4}+\frac{8}{6}\right]$

$=\frac{37}{12}-\frac{(21+16)}{12}$

$=\frac{37}{12}-\frac{37}{12}=0$