The value of $36^{0}$ in radians is

\frac{π}{2}

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\frac{2 π}{5}

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\frac{π}{5}

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π

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Solution

The correct option is C $\frac{π}{5}$
$180^{\circ} = π r a d i a n 1^{\circ} = \frac{π}{180^{\circ}} r a d i a n ∴ 36^{\circ} = \frac{π \times 36^{\circ}}{180^{\circ}} = \frac{π}{5} r a d i a n$

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Similar questions

Q. The values of

^{'} a^{'}

and

^{'} b^{'}

so that the function

f (x)

⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩ \begin{matrix} x + a \sqrt{2} sin x, & 0 \leq x < \frac{π}{4} 2 x cot x + b, & \frac{π}{4} \leq x \leq \frac{π}{2} a cos 2 x - b sin x, & \frac{π}{2} < x \leq π \end{matrix}

is continuous at

x = \frac{π}{4}, \frac{π}{2}

are

How many of the following are matched correctly?

Degree measurement Radian measurement

(A) $180^{\circ}$ (1) $π$
(B) $60^{\circ}$ (2) $\frac{π}{6}$
(C) $0^{\circ}$ (3) 0
(D) $120^{\circ}$ (4) $\frac{2 π}{6}$
(E) $360^{\circ}$ (5) $2 π$
(F) $30^{\circ}$ (6) $\frac{π}{3}$
(G) $90^{\circ}$ (7) $\frac{π}{2}$
(H) $45^{\circ}$ (8) $\frac{π}{4}$
(I) $270^{\circ}$ (9) $3 π$