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Byju's Answer
Standard VIII
Mathematics
Division of a Polynomial by a Monomial
The value of ...
Question
Question 31
The value of
(
3
x
3
+
9
x
2
+
27
x
)
÷
3
x
is
a)
x
2
+
9
+
27
x
b)
3
x
3
+
3
x
2
+
27
x
c)
3
x
3
+
9
x
2
+
9
d)
x
2
+
3
x
+
9
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Solution
d)
x
2
+
3
x
+
9
→
We have,
(
3
x
3
+
9
x
2
+
27
x
)
÷
3
x
=
3
x
3
+
9
x
2
+
27
x
3
x
=
3
x
3
3
x
+
9
x
2
3
x
+
27
x
3
x
=
x
2
+
3
x
+
9
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18
Similar questions
Q.
Question 31
The value of
(
3
x
3
+
9
x
2
+
27
x
)
÷
3
x
is
a)
x
2
+
9
+
27
x
b)
3
x
3
+
3
x
2
+
27
x
c)
3
x
3
+
9
x
2
+
9
d)
x
2
+
3
x
+
9
Q.
lim
x
→
1
x
4
+
3
x
3
−
13
x
2
−
27
x
+
36
x
2
+
3
x
−
4
Q.
Question 24
Factorise
(i)
2
x
3
–
3
x
2
–
17
x
+
30
(ii)
x
3
–
6
x
2
+
11
x
–
6
(iii)
x
3
+
x
2
−
4
x
−
4
(iv)
3
x
3
–
x
2
−
3
x
+
1
Q.
Solve the following equations:
x
4
+
8
9
x
2
+
1
=
3
x
3
+
3
x
.
Q.
3x
3
− x
2
− 3x + 1