Question

The value of $3x^3{y}^2$ for $x=1$ and $y=2$ coincides with the value of $4a+b$ for $a=2$ and $b=4$.

• A. True
• B. False

Answer 1

The correct option is A

True

For $x=1$ and $y=2$,

$3x^3{y}^2$ = $3\times 1^3\times 2^2$ = $12$

For $a=2$ and $b=4$,

$4a+b$ = $(4\times 2)+4$ = $8+4$ = $12$

Hence the value of $3x^3{y}^2$ for $x=1$ and $y=2$ coincides with the value of $4a+b$ for $a=2$ and $b=4$.

i.e. the given statement is true.