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Question

The value of 4+2(1+2)log2+2(1+22)2!(log2)2+2(1+23)3!(log2)3+ is

A
10
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B
12
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C
log(3242)
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D
log(2232)
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Solution

The correct option is B 12
4+2(1+2)log2+2(1+22)(log2)22!+2(1+23)(log2)33!+
=2(1+log2+(log2)22!+)+2(1+2log2+(2log2)22!+)
=2(elog2)+2(e2log2)
=2×2+2elog4=4+2×4=12

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