Question

The value of $4{\cos }^2{60}^0+4{\tan }^2{45}^0-{\csc }^2{30}^0$ is

• A. $0$
• B. $2$
• C. $1$
• D. $\frac{1}{2}$

Answer 1

The correct option is C $1$

$4{\cos }^2{60}^0+4{\tan }^2{45}^0-{\csc }^2{30}^0$
$=4\left(\frac{1}{2}\right){}^2+4\left(1\right)-2^2$
$=1+4-4$
$=1$
Hence answer is C