The value of 4 cot-245-sec-260-sin-260-cos-290- is1-205-23-4

The correct option is D 3/44 cot^245^∘ sec^260^∘+sin^260^∘+cos^290^∘ =4(1)^2 (2)^2+(√(3)/2 )^2+0 =3/4 ...

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The value of $4 c o t^{2} 45^{\circ} - s e c^{2} 60^{\circ} + s i n^{2} 60^{\circ} + c o s^{2} 90^{\circ}$ is

\frac{1}{2}

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\frac{3}{4}

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\frac{5}{2}

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0

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4 c o t^{2} 45^{\circ} - s e c^{2} 60^{\circ} + s i n^{2} 60^{\circ} + c o s^{2} 90^{\circ}

(c o s e c^{2} 45^{\circ} s e c^{2} 30^{\circ}) (s i n^{2} 30^{\circ} + 4 c o t^{2} 45^{\circ} - s e c^{2} 60^{\circ})

4 c o t^{2} 45^{\circ} - s e c^{2} 60^{\circ} + s i n^{2} 60^{\circ} + c o s^{2} 90^{\circ}

\sin^{- 1} (x - \frac{x^{2}}{2} + \frac{x^{3}}{4} - \frac{x^{4}}{8} + - - - - \infty) = \frac{Λ}{6}

|x| < 2

1 . \frac{2}{3} 2 . \frac{3}{2} 3 . \frac{- 2}{3} 4 . \frac{- 3}{2}

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