The value of 52xyz(xy+yz+xz+y2)(z+x)÷104xy(xy+xz+yz+y2) is:
z(z+x)2
z(z−x)2
x(z−x)2
x(z+x)2
52xyz(xy+yz+xz+y2)(z+x)÷104xy(xy+xz+yz+y2) =52xyz(xy+yz+xz+y2)(z+x)104xy(xy+xz+yz+y2) =z(xy+yz+xz+y2)(z+x)2(xy+yz+xz+y2) =12(z)(x+z) ∴ the required value isz(z+x)2
The value of 52xyz(xy+yz+xz+y2)(z+x)×104xy(xy+xz+yz+y2) is: