Question

The value of $(6.32{)}^2\times \sqrt[4]{483.94}$ is equal to

• A. $99$
• B. $110$
• C. $121$
• D. $132$

Answer 1

The correct option is C $121$

Let $y=(6.32{)}^2\times \sqrt[4]{483.94}$
Taking $\log$ on both sides, we get
$\log y=2\log \left(6.32\right)+\frac{1}{4}\log 83.94$

$\log y=2\left(0.8007\right)+\frac{1}{4}\left(1.9240\right)=2.0824$
$y=antilog\left(2.0824\right)=120.9=121$