The value of 6 x y-3 y2-6 x y-3 y2 is A- 72 xy 2- 36 xy 2C- 72 x 2D- 18 y 2

The correct option is A 72xy^2We know that, (a+b)^2 = a^2 + 2ab + b^2 ....(1) nbsp;(a b)^2 = a^2 2ab + b^2 ....(2) Subtracting (2) from (1), (a+b)^2 nbs ...

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Byju's Answer

Standard VIII

Mathematics

Algebraic Identity: (a - b)^2 = a^2 + b^2 - 2ab

The value of ...

Question

The value of $(6 x y + 3 y)^{2} - (6 x y - 3 y)^{2}$ is .

72 x y^{2}

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36 x y^{2}

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72 x^{2}

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18 y^{2}

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Solution

The correct option is A $72 x y^{2}$
We know that,
$(a + b)^{2} = a^{2} + 2 a b + b^{2} . . . . (1) (a - b)^{2} = a^{2} - 2 a b + b^{2} . . . . (2)$
Subtracting (2) from (1),
$(a + b)^{2} - (a - b)^{2} = a^{2} + 2 a b + b^{2} - a^{2} - + 2 a b + - b^{2} = 4 a b$

Here, a = 6xy and b = 3y,
$\Rightarrow (6 x y + 3 y)^{2} - (6 x y - 3 y)^{2} = 4 \times 6 x y \times 3 y$
$= 72 x y^{2}$

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The value of (6xy+3y)2−(6xy−3y)2 is .

The correct option is A 72xy2We know that, (a+b)2=a2+2ab+b2....(1)(a−b)2=a2−2ab+b2....(2) Subtracting (2) from (1), (a+b)2−(a−b)2=a2+2ab+b2−a2−+2ab+−b2=4ab Here, a = 6xy and b = 3y, ⇒(6xy+3y)2−(6xy−3y)2=4×6xy×3y =72xy2

The value of $(6 x y + 3 y)^{2} - (6 x y - 3 y)^{2}$ is .