The value of 7log21615+5log22524+3log28180 is
1
log2105
log2980
log289
Explanation for the correct option:
Given, 7log21615+5log22524+3log28180
=7log216-7log215+5log225-5log224+3log281-3log280=28log22-7log25-7log23+10log25-5log28-5log23+12log23-3log216-3log25[∵logabn=nlogab]=28log22-15log22-12log22-7log25+10log25-3log25-7log23-5log23+12log23[∵logaa=1]=log22+0+0=1
Hence, the correct option is option (A), 1.