The value of 8 x 2 x 96 ÷ (12 x 4) is :
The maximum and the minimum value of 3x4 – 8x3 + 12x2 – 48x + 1 on the interval [1,4]
Find the maximum value and the minimum value of 3x4−8x3+12x2−48x+25 on the interval [0,3].