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Question

The value of 81(1/log53)+27log936+3(4/log79) is

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Solution

We know that alogab=b

81(1/log53)+27log936+3(4/log79)
=(34)log35+(33)log3262+34log97
=3log354+(33)log36+34log327
=54+3log363+32log37
=625+63+3log372
=625+216+72
=890



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