The value of 81 1-log5 3 -27log9 36-34-log7 9 is equal to

81^ ( 1/log_5 3 )+27^log_9 36+3^4/log_7 9 =3^log_3 5^4+3^log_3 36^3/2+3^log_3 7^4/2 =5^4 + 36^3/2+7^2 = 890 ...

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Fundamental Laws of Logarithms

The value of ...

Question

The value of $81^{(\frac{1}{l o g_{5} 3})} + 27^{l o g_{9} 36} + 3^{\frac{4}{l o g_{7} 9}}$ is equal to

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625

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216

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890

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81^{(\frac{1}{l o g_{5} 3})} + 27^{l o g_{9} 36} + 3^{\frac{4}{l o g_{7} 9}}

49^{(1 - {log}_{7} 2)} + 5^{- {log}_{5} 4}

l = log \frac{5}{7}, m = log \frac{7}{9}

n = 2 (log 3 - log \sqrt{5})

7^{l + m + n}

l = log \frac{5}{7}, m = log \frac{7}{9}

n = 2 (log 3 - log \sqrt{5});

l + m + n

81^{(1 / {log}_{5} 3)} + 27^{{log}_{9} 36} + 3^{(4 / {log}_{7} 9)}

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