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Question

The value of 81(1log5 3)+27log9 36+34log7 9 is equal to


A

49

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B

625

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C

216

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D

890

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Solution

The correct option is D

890


81(1log5 3)+27log9 36+34log7 9

=34log3 5+33log3 3612+3log3 742

=3log3 54+3log3 3632+3log3 742

=54+3632+72=890


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