The value of 94-3- 272-3- 33-2 is -

The correct option is A 3^136 We need to find value of #160; (9^4/3÷ 27^2/3)× 3^3/2 9^4/3=3^8/3 and 27^2/3=3^6/3 So, 3^8/33^6/3 ...

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Byju's Answer

Standard XII

Mathematics

Summation by Sigma Method

The value of ...

Question

The value of $(9^{4 / 3} \div 27^{2 / 3}) \times 3^{3 / 2}$ is _______.

3^{\frac{9}{5}}

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3^{\frac{13}{6}}

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3^{\frac{37}{6}}

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3^{4}

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Solution

The correct option is A $3^{\frac{13}{6}}$
We need to find value of $(9^{4 / 3} \div 27^{2 / 3}) \times 3^{3 / 2}$
$9^{4 / 3} = 3^{8 / 3}$ and $27^{2 / 3} = 3^{6 / 3}$
So, $\frac{3^{8 / 3}}{3^{6 / 3}}$ $=$ $3^{8 / 3 - 6 / 3}$ $=$ $3^{2 / 3}$ ,
$\Rightarrow 3^{2 / 3}$ . $3^{3 / 2}$ $=$ $3^{(2 / 3 + 3 / 2)}$ $=$ $3^{13 / 6}$
Hence, B is the right option.

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Similar questions

Q. Simplify

(9^{4 / 3} \div 27^{2 / 3}) \times 3^{3 / 2}

{(\frac{x}{2} + y + \frac{z}{3})}^{3} + {(\frac{x}{3} - \frac{2 y}{3} + z)}^{3} + {(- \frac{5 x}{6} - \frac{y}{3} \frac{4 z}{3})}^{3}

Given a = 6 + √3
⇒ (1/a) = 1 / (6 + √3)
Multiply and divide by (6 − √3)
⇒ (1/a) = (6− √3) / [(6 + √3)(6 − √3)]
⇒ (1/a) = (6 − √3) / [36 − 3]
⇒ (1/a) = (6− √3)/33
∴ a - (1/a) = (6 + √3) -(6 − √3)/33
= [33(6 + √3) - (6 - √3)]/33
= [32*6 + 34*√3]/33
= [192 + 34√3]/33

Answer : [192 + 34√3]/33

Why does 1/a come above

Q. Find the value of

\sqrt{\frac{6 + 2 \sqrt{3}}{33 - 19 \sqrt{3}}}

- 33 y = 6 (3 z + 3) - 39 y

6 y - 22 = c (z - 3)

For what value of

c

does the above system of linear equations in the variables

y

and

z

have infinitely many solutions?

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The value of (94/3÷272/3)×33/2 is _______.

The correct option is A 3136We need to find value of (94/3÷272/3)×33/294/3=38/3 and 272/3=36/3So, 38/336/3 = 38/3−6/3 = 32/3, ⇒32/3.33/2 = 3(2/3+3/2) = 313/6Hence, B is the right option.

The value of $(9^{4 / 3} \div 27^{2 / 3}) \times 3^{3 / 2}$ is _______.