The value of $9 s e c^{2} A - 9 {tan}^{2} A$ is:

-1

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-9

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Solution

The correct option is B 9
9

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Similar questions

(t a n^{2} A s e c^{2} B - s e c^{2} A t a n^{2} B) =

(i) (s i n^{2} A c o s^{2} B - c o s^{2} A s i n^{2} B) = (s i n^{2} A - s i n^{2} B)

(i i) (t a n^{2} A s e c^{2} B - s e c^{2} A t a n^{2} B) = (t a n^{2} A - t a n^{2} B)

△ A B C, tan A tan B tan C = 9

{tan}^{2} A + {tan}^{2} B + {tan}^{2} C = λ

△ A B C

tan A . tan B . tan C = 9

{tan}^{2} A + {tan}^{2} B + {tan}^{2} C = k

If $s i n A = c o s A$ , then $2 t a n^{2} A - 2 s e c^{2} A + 5 =$ ___

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