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Byju's Answer
Standard IX
Mathematics
Expansion of (a ± b)²
The value of ...
Question
The value of (99)
2
is_____
A
9901
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B
9801
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C
9981
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D
9991
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Solution
The correct option is
B
9801
(99)
2
= (100 - 1)
2
.
Using the identity:
(a-b)
2
= (a)
2
-2ab+(b)
2
,
(100 - 1)
2
= (100)
2
-2(1)(100)+(1)
2
= 9801.
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