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Question

The value of 9x2+49y2−42xy when x=15 and y=3 is ___________.

A
636
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B
576
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C
456
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D
386
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Solution

The correct option is B 576
Given expression is f(x,y)=9x2+49y242xy
We need to find value of expression at x=15,y=3
f(15,3)=[9×(15)2]+[49×(3)2][42×15×3]
=[9×225]+[49×9][42×45]
=2025+4411890
=576

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