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Question

Question 32

The value of (a+b)2+(ab)2 is
a) 2a+2b
b) 2a2b
c) 2a2+2b2
a) 2a2+2b2

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Solution

We have,
(a+b)2+(ab)2=(a2+b2+2ab)+(a2+b22ab)
[(a+b)2=a2+b2+2ab and (ab)2=a2+b22ab]
=(a2+a2)+(b2+b2)+(2ab2ab) [combining the like terms]
=2a2+2b2

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