The value of a car, bought for ₹4,40,000 depreciates each year by 10% of its value at the beginning of that year. So, its value becomes ₹3,08,000 after three years.

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Solution

The value of a car i.e. principal = ₹4,40,000
Rate of depreciation (R%) = 10% per annum
Time period (T) = 3 yr
The value of the car after depreciation in 3 yr is given by
$A = P {(1 - \frac{R}{100})}^{r} = 4, 40, 000 {(1 - \frac{10}{100})}^{3} = 4, 40, 000 \times \frac{9}{10} \times \frac{9}{10} \times \frac{9}{10} = 440 \times 729 = ₹ 3, 20, 760$

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The value of a car, bought for ₹4,40,000 depreciates each year by 10% of its value at the beginning of that year. So, its value becomes ₹3,08,000 after three years.

The value of a car i.e. principal = ₹4,40,000 Rate of depreciation (R%) = 10% per annum Time period (T) = 3 yr The value of the car after depreciation in 3 yr is given by A=P(1−R100)r=4,40,000(1−10100)3=4,40,000×910×910×910=440×729=₹ 3,20,760