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Question

The value of a for which ax2+sin1(x22x+2)+cos1(x22x+2)=0 has a real solution is

A
π2
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B
π2
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C
2π
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D
2π
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Solution

The correct option is B π2
ax2+sin1((x1)2+1)+cos1((x1)2+1)=0
ax2+π2=0
x2=π2a
x2=π2a ...(i)
And
1(x1)2+11
2(x1)20
(x1)20
There is only one possibility
(x1)2=0
x=1
Substituting in 1, we get
a=π2

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