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Question

The value of a for which one root of the quadratic equation (a25a+3)x2+(3a1)x+2=0 is twice as large as the other is:

A
32
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B
23
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C
23
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D
32
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Solution

The correct option is B 23
Given equation is (a25a+3)x2+(3a1)x+2=0
Let the roots be p and 2p
p+2p=13aa25a+3,

& p×2p=2a25a+3

2[1(13a)29(a25a+3)2]=2a25a+3

(13a)2a25a+3=99a26a+19a2+45a27=039a=26a=23

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