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Question

The value of a for which the curves y2=4x and x2+y2āˆ’2ax=0 intersect exactly at one point is

A
1
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B
3
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C
2
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D
0
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Solution

The correct option is C 2
Substituting y2=4x in x2+y22ax=0 gives
x2+4x2ax=0
x2+(42a)x=0
For this quadratic equation to have only one solution, discriminant has to be equal to zero.
(42a)2=0
42a=0
a=2

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