The value of 'a'for which the equation (a2+4a+3)x2+(a2−a−2)x+(a+1)a=0 has more than two roots is
A
1
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B
2
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C
-2
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D
-1
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Solution
The correct option is D -1 (a2+4a+3)x2+(a2−a−2)x+(a+1)a=0 (a+1)(a+3)x2+(a+1)(a−2)x+(a+1)a=0 (a+1)[(a+3)x2+(a−2)x+a]=0
If a=-1, then quadratic have more than two roots.