The value of a for which the equations x2−3x+a=0 and x2+ax−3=0 have a common root is
2
Given equations are x2–3x+a=0 …… (i)
and x2+ax –3=0 …… (ii)
Subtract (ii) from (i), we get
−3x−ax+a+3=0
(a+3)(−x+1)=0
⇒ either a= –3 or x=1
When a= –3, the two equations are identical. So, we take x=1,
which is the common root of the two equations.
Substituting x=1 in (ii), we get 1+a −3=0 ⇒ a=2