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Question

The value of 'a' for which the function f(x)=(a+2)x33ax2+9ax1 decreases for all real values of x is

A
(,3]
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B
(,3)
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C
(,2)
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D
(,3][0,)
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Solution

The correct option is B (,3)
decreasing or strictly decreasing => f(x)<0
monotonically decreasing => f(x)<=0.
f(x)=3(a+2)x26ax+9a
Given f(x)<0 => a+2<0,(6a)24(3(a+2))(9a)<0 (from quadratic equations graph concept)
after simplifying aϵ(,3)

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