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Question

The value of a, for which the points A,B,C with position vectors 2^i^j+^k,^i3^j5^k,a^i3^j+^k respectively are the vertices of a right angled triangle with C=π2 are:

A
1
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B
2
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C
1
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D
2
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Solution

The correct options are
A 1
D 2
BC=OCOB
=a^i3^j+^k(^i3^j5^k)
=(a1)^i+6^k
CA=OAOC
=2^i^j+^k(a^i3^j+^k)
=(2a)^i+2^j
BC.CA=[(a1)^i+6^k].[(2a)^i+2^j]
=(a1)(2a)+0
since ^i.^i=1,^i.^j=0
(a1)(2a)=0
a=1,2

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