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Question

The value of a for which the quadratic equation 3x2+2(a2+1) x+ (a2-3a+2) =0 possesses real roots of the opposite sign lies in

A
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B
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C
(1, 2)
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D
(3/2, 2)
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E
[1, 2]
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Solution

The correct option is C (1, 2)

Answer = option (c)

To have 2 roots of the opposite sign, the product of the roots need to be negative and the equation should have real roots

4(a2+1)2 -12(a2-3a+2) ≥0 and (a2-3a+2)/3< 0 i.e. (a-1)(a-2)<0 or 1<a<2


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