The value of a for which the quadratic equation 3x2+2(a2+1) x+ (a2-3a+2) =0 possesses real roots of the opposite sign lies in
Answer = option (c)
To have 2 roots of the opposite sign, the product of the roots need to be negative and the equation should have real roots
4(a2+1)2 -12(a2-3a+2) ≥0 and (a2-3a+2)/3< 0 i.e. (a-1)(a-2)<0 or 1<a<2