Question

The value of $a$ if $64,16,a$ are in GP.

• A. 4
• B. 5
• C. 6
• D. 7

Answer 1

Answer: (A)

4

Given sequence $64,16,a$ is a GP & we know that condition to be in GP for $x,y,z$ is $y^2=xz$

Therefore,

${16}^2=64a256=64aa=\frac{256}{64}a=4$