The value of $a$ if the series $4, a, 16$ are in GP

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none of these

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Solution

The correct option is B 8
Given sequence $4, a, 16$ is a GP & we know that condition to be in GP for $x, y, z$ is $y^{2} = x z$
Therefore,
$a^{2} = 4 (16) a^{2} = 64 a = \sqrt{64} a = 8$

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