Question

The value of $‘a^{\prime }$ in the following equation is:
${\left[\frac{9}{2}\right]}^{-3}\times {\left[\frac{2}{9}\right]}^{-6}={\left[\frac{2}{9}\right]}^{2a-1}$

• A. $-2$
• B. $2$
• C. $-1$
• D. $1$

Answer 1

The correct option is C $-1$

$a^m\times a^n=a^{m+n}$
Using the above law, we get the equation as:
${\left[\frac{2}{9}\right]}^{-3}={\left[\frac{2}{9}\right]}^{2a-1}$
Therefore, the value of $a$ is $-1$.