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Question

The value of alog(b/c)×blog(c/a)×clog(a/b) is

A
0
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B
1
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C
-1
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D
None of these
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Solution

The correct option is B 1
We know that alogb=bloga and log(a/b)=logalogb.

Now, using above properties:

=alog(b/c)×blog(c/a)×clog(a/b)= alog(b)logc×blog(c)loga×clog(a)logb

=alogbalogc×blogcbloga×clogaclogb=1................[ because xlogy=ylogx]

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