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Question

The value of a machine depreciated by 10% per year during the first two years and 15% per year during the third year. Express the total depreciation of the machine, as per cent, during the three years.

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Solution

Let the original value be be M
After being depreciated at R=10 %, for 2 years we have its value =OriginalValue×(1R100)N=M×(110100)2=M×0.9×0.9=Rs0.81M
For the third year, at R=15 %, we have its value still reduced to
=0.81M×(115100)1=0.81M×0.85=Rs0.6885M
So, total % change in 3 years =M0.6885MM×100=31.15 %


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