The value of a machine depreciates at the rate of $10 %$ every year. It was purchased $3$ years ago. If its present value is $8748$ , its purchase price was.

8, 000

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85, 000

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1, 000

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12, 000

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Solution

The correct option is D $12, 000$
Machine's purchase price was
$= \frac{P}{{(1 - \frac{R}{100})}^{w}} = R s \frac{8748}{{(1 - \frac{10}{100})}^{3}} = R s \frac{8748}{{(\frac{9}{100})}^{3}} = R s 8748 \times \frac{10}{9} \times \frac{10}{9} \times \frac{10}{9} = R s 12000$

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The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is 8748, its purchase price was.

The correct option is D 12,000Machine's purchase price was=P(1−R100)w=Rs8748(1−10100)3=Rs8748(9100)3=Rs8748×109×109×109=Rs12000

The value of a machine depreciates at the rate of $10 %$ every year. It was purchased $3$ years ago. If its present value is $8748$ , its purchase price was.

The correct option is D $12, 000$
Machine's purchase price was
$= \frac{P}{{(1 - \frac{R}{100})}^{w}} = R s \frac{8748}{{(1 - \frac{10}{100})}^{3}} = R s \frac{8748}{{(\frac{9}{100})}^{3}} = R s 8748 \times \frac{10}{9} \times \frac{10}{9} \times \frac{10}{9} = R s 12000$