The value of acceleration due to gravity on the surface of the earth is 9.8m/s^2. Find the value on the surface of the moon.given that mass of the earth is 6×10^24 kg; radius of the earth is 6.4×10^6m;mass of the moon is 7.10^24kg;and the radius of the moon is 1.74×10^6m

Open in App

Solution

Suggest Corrections

Similar questions

Given mass of earth is 6 × $10^{24}$ kg and mean radius of earth is 6.4 × $10^{6}$ m. Calculate the value of acceleration due to gravity (g) on the surface of the earth.

Q. Solve:
Estimate the mass of the earth, given, radius of the earth

= 6.4 \times 10^{6} m

, acceleration due to gravity

= 9.8 m / s^{2}

and gravitational constant

= 6.67 \times 10^{- 11} S . I .

units.

Q. The mass of earth is

80

times that of moon and its diameter is double that of moon. If the value of acceleration due to gravity on earth is

9.8 m / s^{2}

, then the value of acceleration due to gravity on moon will be

Q. If the acceleration due to gravity g at the earth's surface is

9.8 m s^{- 2}

and mass of the earth is 80 times that of moon, radius of earth 4 times that of the moon, the value of g at the moon's surface will be approximately equal to?

The acceleration due to gravity at the surface of the moon is 1.67 $\frac{m}{{s e c}^{2}}$ . If the radius of the moon is 1.74 $\times$ $10^{6}$ m. Find the mass of the moon. ( Given: G = 6.67 $\times$ $10^{- 11}$ $\frac{N m^{2}}{{k g}^{2}}$ )

Join BYJU'S Learning Program