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Equation of Motion of Free Fall

the value of ...

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the value of acceleration due to gravity will be 1% of its value at the surface of earth at a height of(take Re=6400km)

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Similar questions

Q. If the acceleration due to gravity, g, is 10

m / s^{2}

at the surface of the earth (radius 6400 km), then at a height of 1600 km the value of g will be ( in

m / s^{2}

)

Q. The height at which the value of acceleration due to gravity becomes

50 %

of that at the surface of the earth

.

(radius of the earth =

6400 k m

Q. At a place, value of acceleration due to gravity

g

2

% of its value on the surface of the earth (Radius of earth =

6400 k m

). The place is:-

Q. Acceleration due to gravity at earth's surface is '

g

^{2}

. Find the effective value of acceleration due to gravity at a height of

32 k m

from sea level :(

R_{e} = 6400 k m

Q. At what approximate height from the earth's surface, acceleration due to gravity will be half the value of g? [radius of earth

R_{e} = 6.4 \times 10^{6} m]

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Equation of Motion of Free Fall

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