The value of α, for which the points A,B,C with position vectors 2^i−^j+^k,^i−3^j−5^k and α^i−3^j+^k are the vertices of a right angled triangle with ∠C=π2 are
A
−2 and 1
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B
2 and −1
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C
2 and 1
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D
−2 and −1
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Solution
The correct option is C2 and 1 →AC=(α−2)^i−2^j →BC=(α−1)^i →AC⊥→BC →AC.→BC=0 (α−2)(α−1)=0 α=2,1