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Byju's Answer

Standard XII

Physics

Magnetic Dip

The value of ...

Question

The value of angle of dip is zero at the magnetic equator because on it :

V

and

H

are equal

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the value of

V

and

H

is zero

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the value of

V

is zero

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horizontal direction

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Solution

The correct option is D the value of $V$ is zero
Because at that point value of $V = 0$ & $I = H$
$I =$ $\sqrt{H^{2} + V^{2}}$
$θ = 0$
If $I = H$

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Similar questions

At a place, the value of $B_{H}$ & $B_{V}$ are $0.4 \times 10^{- 4} T$ and $0.3 \times 10^{- 4}$ respectively, the angle of dip is :

Q. Which one of the following statements is true for the speed

v

and the acceleration

a

of a particle executing simple harmonic motion?

Q. Magnetic field of earth is identical to magnetic field of a giant magnet held

20^{o}

west of geographic

N - S

at the centre of earth. At equator, horizontal component of earth is

0.32 G

. Vertical component can be calculated from the relation

V = H tan δ

, where

δ

is angle of dip at the place. The value of

δ = 0^{o}

at equator and

δ = 90^{o}

at poles. What is the order of magnetic declination at a place on earth :

Q. Prove that

I^{2} = H^{2} + V^{2}

and

t a n q = \frac{V}{H}

; where for terrestrial magnetism

θ

angle of dip, H horizontal component and vertical component.

Q. At a place the value of

B_{H}

and

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are

0.4 \times 10^{- 4}

and

0.3 \times 10^{- 4}

respectively. The resultant earths magnetic field is :

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The value of angle of dip is zero at the magnetic equator because on it :

The correct option is D the value of V is zeroBecause at that point value of V=0 & I=H I= √H2+V2θ=0If I=H

The correct option is D the value of $V$ is zero
Because at that point value of $V = 0$ & $I = H$
$I =$ $\sqrt{H^{2} + V^{2}}$
$θ = 0$
If $I = H$