Question

The value of$\angle \mathrm{QSR}$ is

Answer 1

Find the value of$\angle \mathrm{QSR}$

$\mathrm{PQ}$is parallel to$\mathrm{RF}$

$$\begin{gathered} \angle \mathrm{PQS}=60°........\left(\mathrm{Given}\right) \\ \angle \mathrm{PQS}=\angle \mathrm{RSE}.......\left(\mathrm{Corresponding}\mathrm{angles}\right) \\ \therefore \angle \mathrm{RSE}=60° \\ \angle \mathrm{RSE}+\angle \mathrm{QSR}=180°......\left(\mathrm{angles}\mathrm{in}\mathrm{linear}\mathrm{pair}\right) \\ 60°+\angle \mathrm{QSR}=180° \\ \angle \mathrm{QSR}=180°-60° \\ \angle \mathrm{QSR}=120° \end{gathered}$$

$\therefore$ The value of$\angle \mathrm{QSR}$ is$120°.$