The value of b and c for which the identity f(x+1) - f(x) = 8x + 3 is satisfied, where f(x)=bx2+cx+d are
b = 4, c = –1
∵ f(x+1)−f(x)=8x+3⇒{b(x+1)2+c(x+1)+d}−{bx2+cx+d}=8x+3⇒b{(x+1)2−x2}+c=8x+3⇒b(2x+1)+c=8x+3 on comparing
2b = 8 and b + c = 3
Then, b = 4 and c = –1