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Question

The value of ⎢ ⎢ ⎢1tanθ4tanθ41⎥ ⎥ ⎥⎢ ⎢ ⎢1tanθ4tanθ41⎥ ⎥ ⎥1 is

A
⎢ ⎢ ⎢cosθ2sinθ2sinθ2cosθ2⎥ ⎥ ⎥
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B
⎢ ⎢ ⎢cosθ2sinθ2sinθ2cosθ2⎥ ⎥ ⎥
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C
⎢ ⎢ ⎢sinθ2cosθ2cosθ2sinθ2⎥ ⎥ ⎥
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D
⎢ ⎢ ⎢sinθ2cosθ2cosθ2sinθ2⎥ ⎥ ⎥
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Solution

The correct option is A ⎢ ⎢ ⎢cosθ2sinθ2sinθ2cosθ2⎥ ⎥ ⎥
=⎢ ⎢ ⎢1tanθ4tanθ41⎥ ⎥ ⎥1(1+tan2θ4)⎢ ⎢ ⎢1tanθ4tanθ41⎥ ⎥ ⎥

=1sec2θ4⎢ ⎢ ⎢1tanθ4tanθ41⎥ ⎥ ⎥⎢ ⎢ ⎢1tanθ4tanθ41⎥ ⎥ ⎥

=cos2θ4⎢ ⎢ ⎢1tan2θ42tanθ42tanθ41tan2θ4⎥ ⎥ ⎥

=cos2θ4⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢cos2θ4sin2θ4cos2θ42sinθ4cosθ42sinθ4cosθ4cos2θ4sin2θ4cos2θ4⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥

=⎢ ⎢ ⎢cosθ2sinθ2sinθ2cosθ2⎥ ⎥ ⎥

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