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Byju's Answer
Standard XII
Mathematics
Middle Terms
The value of ...
Question
The value of
(
30
0
)
(
30
10
)
−
(
30
1
)
(
30
11
)
+
(
30
2
)
(
30
12
)
−
⋅
⋅
⋅
⋅
⋅
⋅
+
(
30
20
)
(
30
30
)
=
A
60
C
20
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B
30
C
10
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C
60
C
30
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D
40
C
30
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Solution
The correct option is
D
30
C
10
30
C
0
30
C
10
−
30
C
1
30
C
11
+
⋯
+
30
C
20
30
C
30
This is the coefficient of
x
20
in the expansion of
(
1
+
x
)
30
(
1
−
x
)
30
⇒
Coefficient of
x
20
in the expansion of
(
1
−
x
2
)
30
Now, Coefficient of
x
20
in the expansion of
(
1
−
x
2
)
30
is
30
∑
r
=
0
(
−
1
)
r
30
C
r
x
2
r
Substituting
r
=
10
, we get
Coefficient of
x
20
as
30
C
10
Hence, option B.
Suggest Corrections
0
Similar questions
Q.
The value of
(
30
0
)
(
30
10
)
-
(
30
1
)
(
30
11
)
+
(
30
2
)
(
30
12
)
......+
(
30
20
)
(
30
30
)
is, where
(
n
r
)
=
n
C
r
.
Q.
The value of
(
30
0
)
(
30
10
)
−
(
30
1
)
(
30
11
)
+
(
30
2
)
(
30
12
)
−
.
.
.
+
(
30
20
)
(
30
30
)
is where
(
n
r
)
=
n
C
r
Q.
Let
m
,
n
∈
N
and
gcd
(
2
,
n
)
=
1.
If
30
(
30
0
)
+
29
(
30
1
)
+
⋯
+
2
(
30
28
)
+
1
(
30
29
)
=
n
⋅
2
m
,
then
n
+
m
is equal to
(
Here
(
n
k
)
=
n
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)
Q.
Find the value of 10 + 20 + 30 + 40 + 50 + 60.
Q.
Construct a chromosome map with the given crossover frequency of each of the genes.
Gene
Frequency of crossover
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30%
B-C
45%
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A-D
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