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Question

The value of (300)(3010)(301)(3011)+(302)(3012)+(3020)(3030)=

A
60C20
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B
30C10
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C
60C30
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D
40C30
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Solution

The correct option is D 30C10
30C0 30C10 30C1 30C11++ 30C20 30C30
This is the coefficient of x20 in the expansion of (1+x)30(1x)30
Coefficient of x20 in the expansion of (1x2)30
Now, Coefficient of x20 in the expansion of (1x2)30 is
30r=0(1)r 30Cr x2r
Substituting r=10, we get
Coefficient of x20 as 30C10
Hence, option B.

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