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Question

The value of ∣ ∣111abca2b2c2∣ ∣ is

A
(a+b)(b+c)(c+a)
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B
(ab)(bc)(ca)
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C
a3+b3+c33abc
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D
(ab)(bc)(ac)
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Solution

The correct option is A (ab)(bc)(ca)
Let Δ=∣ ∣ ∣111abca2b2c2∣ ∣ ∣

Applying C2C2C1;C3C3C1

Δ=∣ ∣ ∣100abacaa2b2a2c2a2∣ ∣ ∣

=(ba)(c2a2)(ca)(b2a2)=(ba)(ca)(c+a)(ba)(b+a)(ca)=(ba)(ca)(cb)

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