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Question

The value of ∣ ∣ ∣1cos(βα)cos(γα)cos(αβ)1cos(γβ)cos(αγ)cos(βγ)1∣ ∣ ∣ is

A
∣ ∣cosαsinα1cosβsinβ1cosγsinγ1∣ ∣2
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B
∣ ∣sinαcosα0sinβcosβ0sinγcosγ0∣ ∣2
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C
∣ ∣cosαsinα0sinβ0cosβ0cosγsinγ∣ ∣2
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D
None of these
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Solution

The correct option is B ∣ ∣sinαcosα0sinβcosβ0sinγcosγ0∣ ∣2
∣ ∣ ∣1cos(βα)cos(γα)cos(αβ)1cos(γβ)cos(αγ)cos(βγ)1∣ ∣ ∣∣ ∣ ∣cos2α+sin2αcosβcosα+sinβsinαcosαcosγ+sinαsinγcosαcosβ+sinαsinβcos2β+sin2βcosβcosγ+sinβsinγcosαcosγ+sinαsinγcosβcosγ+sinβsinγcos2β+sin2β∣ ∣ ∣=∣ ∣cosαsinα0cosβsinβ0cosγsinγ0∣ ∣∣ ∣cosαsinα0cosβsinβ0cosγsinγ0∣ ∣=∣ ∣sinαcosα0sinβcosβ0sinγcosγ0∣ ∣2.

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