The value of ∣∣ ∣ ∣∣1cos(β−α)cos(γ−α)cos(α−β)1cos(γ−β)cos(α−γ)cos(β−γ)1∣∣ ∣ ∣∣ is
Evaluate ∣∣ ∣∣cosαcosβcos αsin β−sin α−sinβcosβ0sin αcos βsin αsin βcos α∣∣ ∣∣
Using properties of determinants prove the following questions.
∣∣ ∣ ∣∣αα2β+γββ2γ+αγγ2α+β∣∣ ∣ ∣∣=(β−γ)(γ−α)(α−β)(α+β+γ)