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Question

The value of ∣∣ ∣ ∣∣a2bcac+c2a2+abb2acabb2+bcc2∣∣ ∣ ∣∣ is

A
2abc
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B
8abc
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C
4a2b2c2
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D
2a2b2c2
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Solution

The correct option is D 4a2b2c2
∣ ∣ ∣a2bcac+c2a2+abb2acabb2+bcc2∣ ∣ ∣

=a2(b2c2ac(b2+bc))bc(c2(a2+ab)a2bc)+(ac+c2)((a2+ab)(b2+bc)ab3)

=a2b2c2a3b2ca3bc2bc(a2c2abc2a2bc)+(ac+c2)(a3b2+a2bc+ab2+ab2cab3)

=a2b2c2a3b2ca3bc2a2bc3+ab2c3+a2b2c2+a2b2c+a3bc2+a2b2c2+a2b2c2+a2bc3+ab2c2

=4a2b2c2

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