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Byju's Answer
Standard IX
Mathematics
Multiplication of Matrices
The value of ...
Question
The value of
∣
∣ ∣
∣
a
a
+
b
a
+
b
+
c
2
a
3
a
+
2
b
4
a
+
3
b
+
2
c
3
a
6
a
+
3
b
10
a
+
6
b
+
3
c
∣
∣ ∣
∣
is equal to
A
a
3
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B
b
3
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C
c
3
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D
a
3
+
b
3
+
c
3
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Solution
The correct option is
A
a
3
Use
R
2
→
R
2
−
2
R
1
and
R
3
→
R
3
−
3
R
1
⇒
∣
∣ ∣
∣
a
a
+
b
a
+
b
+
c
0
a
2
a
+
b
0
3
a
7
a
+
3
b
∣
∣ ∣
∣
R
3
→
R
3
−
3
R
2
⇒
∣
∣ ∣
∣
a
a
+
b
a
+
b
+
c
0
a
2
a
+
b
0
0
a
∣
∣ ∣
∣
=
a
3
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1
Similar questions
Q.
Prove that
∣
∣ ∣
∣
a
a
+
b
a
+
b
+
c
2
a
3
a
+
2
b
4
a
+
3
b
+
2
c
3
a
6
a
+
3
b
10
a
+
6
b
+
3
c
∣
∣ ∣
∣
=
a
3
.
Q.
∣
∣ ∣
∣
a
a
+
b
a
+
b
+
c
2
a
3
a
+
2
b
4
a
+
3
b
+
2
c
3
a
6
a
+
3
b
10
a
+
6
b
+
3
a
∣
∣ ∣
∣
=
a
3
Q.
Show that
∣
∣ ∣
∣
a
a
+
b
a
+
b
+
c
2
a
3
a
+
2
b
4
a
+
3
b
+
2
c
3
a
6
a
+
3
b
10
a
+
6
b
+
3
c
∣
∣ ∣
∣
=
a
3
Q.
Using properties of determinants, prove that
∣
∣ ∣
∣
a
a
+
b
a
+
b
+
c
2
a
3
a
+
2
b
4
a
+
3
b
+
2
c
3
a
6
a
+
3
b
10
a
+
6
b
+
3
c
∣
∣ ∣
∣
=
a
3
Q.
Prove the following identity:
(
b
+
c
)
3
+
(
c
+
a
)
3
+
(
a
+
b
)
3
−
3
(
b
+
c
)
(
c
+
a
)
(
a
+
b
)
=
2
(
a
3
+
b
3
+
c
3
−
3
a
b
c
)
.
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