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Question

The value of ∣ ∣abc2a2a2bbca2b2c2ccab∣ ∣ is

A
a+b+c
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B
2(a+b+c)
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C
(a+b+c)2
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D
(a+b+c)3
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Solution

The correct option is D (a+b+c)3
Δ=∣ ∣abc2a2a2bbca2b2c2ccab∣ ∣

Applying R1R1+R2+R3

Δ=∣ ∣a+b+ca+b+ca+b+c2bbca2b2c2ccab∣ ∣Δ=(a+b+c)∣ ∣1112bbca2b2c2ccab∣ ∣

Applying C2C2C1;C3C3C1

Δ=(a+b+c)∣ ∣1002bbca02c0cab∣ ∣=(a+b+c)3

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