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Question

The value of ∣ ∣y+zxxyz+xyzzx+y∣ ∣ is equal to

A
xyz
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B
4xyz
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C
3xyz
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D
2xyz
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Solution

The correct option is B 4xyz

Given that,

Δ =
∣ ∣y+zxxyz+xyzzx+y∣ ∣

Here you can either go for straight away evaluation of determinant along the first row or apply some properties and then evaluate. Since applying properties is going to make the final evaluations easier we will go with that method.

Δ=∣ ∣y+zxxyz+xyzzx+y∣ ∣c1c1+c2+c3

= 2 ∣ ∣y+zx+zx+yyz+xyzzx+y∣ ∣c2c2c1c3c3c1

= 2 ∣ ∣y+zx+zx+yz0xyx0∣ ∣c1c1+c2+c3

= 2 ∣ ∣0zyz0xyx0∣ ∣


= 2[-z(-xy)+y(xz)]

= 4 xyz


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